Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 9 - Counting and Probability - Exercise Set 9.2 - Page 539: 38

Answer

a. $60$ b. $56$

Work Step by Step

a. There are $5$ choices for the first object, $4$ choices for the second object, and $3$ for the third object, so there are a total of $60$ possibilities. b. There are 8 choices for the first object and 7 for the second, so by the multiplication rule, there are $8*7 = 56$ total choices.
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