Answer
No, because if it's not onto that means there are elements in the co-domain that are not connected to any element in the domain, which means in the inverse there are elements in the domain that are not connected on the co-domain which invalidate the function definition.
Work Step by Step
No, because if it's not onto that means there are elements in the co-domain that are not connected to any element in the domain, which means in the inverse there are elements in the domain that are not connected on the co-domain which invalidate the function definition.