Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 8 - Relations - Exercise Set 8.1 - Page 448: 1

Answer

0 E 0 because 0 − 0 = 0 = 2• 0, so 2 | (0 − 0). 5 _E 2 because 5 − 2 = 3 and 3 _= 2k for any integer k so 2 not| (5 − 2). (6, 6) ∈ E because 6 − 6 = 0 = 2• 0, so 2 | (6 − 6). (−1, 7) ∈ E because −1 − 7 = −8 = 2• (−4), so 2 | (−1 − 7).

Work Step by Step

have to prove= (m-n) is a even number. 0 E 0 because 0 − 0 = 0 = 2• 0, so 2 | (0 − 0). 5 _E 2 because 5 − 2 = 3 and 3 _= 2k for any integer k so 2 not | (5 − 2). (6, 6) ∈ E because 6 − 6 = 0 = 2• 0, so 2 | (6 − 6). (−1, 7) ∈ E because −1 − 7 = −8 = 2• (−4), so 2 | (−1 − 7).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.