Answer
0 E 0 because 0 − 0 = 0 = 2• 0, so 2 | (0 − 0).
5 _E 2 because 5 − 2 = 3 and 3 _= 2k for any integer k
so 2 not| (5 − 2).
(6, 6) ∈ E because 6 − 6 = 0 = 2• 0, so 2 | (6 − 6).
(−1, 7) ∈ E because −1 − 7 = −8 = 2• (−4), so
2 | (−1 − 7).
Work Step by Step
have to prove= (m-n) is a even number.
0 E 0 because 0 − 0 = 0 = 2• 0, so 2 | (0 − 0).
5 _E 2 because 5 − 2 = 3 and 3 _= 2k for any integer k
so 2 not | (5 − 2).
(6, 6) ∈ E because 6 − 6 = 0 = 2• 0, so 2 | (6 − 6).
(−1, 7) ∈ E because −1 − 7 = −8 = 2• (−4), so
2 | (−1 − 7).