Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 7 - Functions - Exercise Set 7.1 - Page 394: 20

Answer

This is true because $b^0 = 1$.

Work Step by Step

$b^0$ is defined as $1$ for all numbers. Therefore, since the definition of logarithm is the number to which the base must be raised to get the number that is being taken log of, $log_b 1 = 0$ because $b^0 = 1$ for all numbers.
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