Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 6 - Set Theory - Exercise Set 6.1 - Page 349: 2

Answer

See the detail below

Work Step by Step

A = {m ∈ Z | m = 2a for some integer a} and B = {n ∈ Z | n = 2b – 2 for some integer b} To prove that B is a subset of A, we need to show that every element in B is also an element of A. Let's take an element x ∈ B. By definition, x is an integer that satisfies the equation x = 2b - 2 for some integer b. To prove that x ∈ A, we need to show that x can be expressed in the form x = 2a for some integer a. Starting with the equation x = 2b - 2, we can rewrite it as x = 2(b - 1) Let's define a new integer c = b - 1. Now we have x = 2c Since c is an integer (since b is an integer), we have expressed x in the form x = 2a, where a = c. Therefore, for any element x ∈ B, we have shown that x ∈ A. Thus, we have proved that B ⊆ A.
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