Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.2 - Page 257: 23

Answer

180279

Work Step by Step

The sum of first n natural numbers is given by, $\frac{n\times(n+1)}{2}$ 7 + 8 + 9 + 10 + ··· + 600 = (1+2+3+ ... +600) - (1+2+3+ ... +6) = $\frac{600\times601}{2}$ - $\frac{6\times7}{2}$ = 180300 - 21 = 180279
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