Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.8 - Page 225: 3

Answer

(a). $18$ (b). $6$

Work Step by Step

Examine the given algorithm, we can find: (a). Given $x=2,y=3$, we have $x\cdot y\gt0$, execute the $then\ do\ ... \ end\ do$ statements, we get $y=6,x=3$, thus finally we get $z=x\cdot y=18$ (b). Given $x=1,y=1$, we have $x\cdot y\gt0$, execute the $then\ do\ ... \ end\ do$ statements, we get $y=3,x=2$, thus finally we get $z=x\cdot y=6$
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