Answer
True.
Work Step by Step
True.
Proof: Given $a|b$ and $a|c$, let $b=ma$ and $c=na$, where $m,n$ are integers, we have $2b-3c=2ma-3na=(2m-3n)a$. Since $2m-3n$ is also an integer, by definition, we have $a|(2b-3c)$
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.3 - Page 178: 24
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