Answer
This statement is true.
Work Step by Step
Note that $n^3-m^3 = (n-m)(n^2+mn+m^2)$. Since $n-m$ is even and it divides $n^3-m^3$, $n^3-m^3$ must be even, since the product of an even integer with any integer is always even.
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.1 - Page 162: 50
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
