Answer
This statement is false, as $2k^2-5k+2 = (2k-1)(k-2)$.
Work Step by Step
Since $2k^2-5k+2 = (2k-1)(k-2)$, for any $k \geq 4$, the expression must have 2 factors that are both greater than 1. Therefore, the resulting integer cannot be prime, as it has 2 factors in addition to 1 and the number itself, so it cannot be prime and the statement is contradicted.
