Answer
This is false, as $m^2-1 = (m+1)(m-1)$
Work Step by Step
Since $m^2-1 = (m-1)(m+1)$, for any $m \geq 3$, the expression must have at least 2 factors greater than 1, so it cannot be prime. Therefore, the statement is contradicted.
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.1 - Page 162: 35
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