Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 3 - The Logic of Quantified Statements - Exercise Set 3.4 - Page 143: 11

Answer

Invalid by the converse error.

Work Step by Step

Converse Error: $\forall x$ if $P(x)$ then $Q(x)$. $Q(a)$ for a particular $a$. $\therefore P(a)$. (invalid conclusion) In this case P(x) is: x is a cheater. Q(x) is: x sits in the back row. a is Monty.
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