Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 2 - The Logic of Compound Statements - Exercise Set 2.3 - Page 62: 28

Answer

The argument is Invalid due to the converse error

Work Step by Step

If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite $(p →q)$. The set of all irrational numbers is infinite $(q)$ ∴ There are as many rational numbers as there are irrational numbers.$(p)$ The argument form is: p →q q ∴ p Thus this is the typical converse error
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