Basic College Mathematics (9th Edition)

Published by Pearson

Chapter 9 - Basic Algebra - Review Exercises: 97

Answer

$y=-5$

Work Step by Step

We are given the equation $4y-3=7y+12$. We can solve by first adding 3 to both sides. $4y-3+3=7y+12+3$ $4y=7y+15$ Subtract 7y from both sides. $4y-7y=7y-7y+15$ $-3y=15$ Divide both sides by -3. $y=-5$

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