Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - Review Exercises: 37

Answer

$-\frac{1}{2}$

Work Step by Step

$\frac{1}{3}-\frac{5}{6}=\frac{1\times2}{3\times2}-\frac{5}{6}=\frac{2}{6}-\frac{5}{6}=\frac{2-5}{6}=-\frac{3}{6}=-\frac{1}{2}$
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