Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises: 54

Answer

The length of the house is $33$ ft and the width of the house is $28$ ft.

Work Step by Step

Let $x = $ the length of the house $2(x -5) + 2(x) = 122$ $2x - 10 + 2x = 122$ $4x - 10 = 122$ $4x = 132$ $x = \frac{132}{4}$ $x = 33$ ft Let $y = $ the width of the house $y = (x - 5)$ $y = 33 - 5$ $y = 28$ ft
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