Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises - Page 691: 53

The length of the jewelry box is $13$ inches and the width is $5$ inches.

Let $x =$ the width of the jewelry box $2(2x + 3) + 2(x) = 36$ $4x + 6 + 2x = 36$ $6x = 30$ $x = \frac{30}{6}$ $x = 5$ inches Let $y = $ the length of the jewelry box $y = 2x + 3$ $y = 2(5) + 3$ $y = 10 + 3$ $y = 13$ inches