## Basic College Mathematics (9th Edition)

Published by Pearson

# Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises: 41

#### Answer

Lein earned 19,500 dollars while her husband earned 18,000 dollars.

#### Work Step by Step

Let $x =$ money Lien's husband's money (Lien's money) + (Her husband's money) $= 37500$ $(x + 1500) + (x) = 37500$ $2x + 1500 = 37500$ $2x = 36000$ $x = \frac{36000}{2}$ $x = 18,000$ dollars Therefore her husband earned 18,000 dollars. Let $L =$ money Lien earned $L = (x + 1500)$ $L = (18000 + 1500$ $L = 19,500$ dollars Therefore Lien earned \$19,500 dollars.

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