Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - 9.2 Adding and Subtracting Signed Numbers - 9.2 Exercises: 86

Answer

$\dfrac{2}{5}-\dfrac{7}{10}+\Big(-\dfrac{3}{2}\Big)=-\dfrac{9}{5}$

Work Step by Step

$\dfrac{2}{5}-\dfrac{7}{10}+\Big(-\dfrac{3}{2}\Big)$ First, evaluate the subtraction $\dfrac{2}{5}-\dfrac{7}{10}$: $\dfrac{2}{5}-\dfrac{7}{10}+\Big(-\dfrac{3}{2}\Big)=\dfrac{4-7}{10}+\Big(-\dfrac{3}{2}\Big)=-\dfrac{3}{10}+\Big(-\dfrac{3}{2}\Big)=...$ Take out common factor $-1$: $...=-\Big(\dfrac{3}{10}+\dfrac{3}{2}\Big)=...$ Evaluate the sum inside the parentheses and simplify: $...=-\Big(\dfrac{3+15}{10}\Big)=-\Big(\dfrac{18}{10}\Big)=-\dfrac{9}{5}$
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