Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - Review Exercises: 70

Answer

$x = 9$ ft $y = 7.5$ ft The perimeter of the large triangle is $22.5$ ft.

Work Step by Step

1. Using the small triangle, find the ratios between the lengths a) Ratio between $4$ ft and $6$ ft (Large triangle: $6$ ft and $x$) $4a=6$ $a = 1.5$ b) Ratio between $4$ ft and $5$ ft (Large triangle: $6$ ft and $y$) $4a=5$ $a=1.25$ 2. Use the ratios to find $x$ and $y$ a) Finding $x$ $x=6 × 1.5$ $x=9$ ft b) Finding $y$ $y=6×1.25$ $y=7.5$ ft Currently, the lengths in the large triangle are $6$ ft, $7.5$ ft and $9$ ft. 3. Find the perimeter of the large triangle Let $P=$ perimeter of the large triangle $P=6 + 7.5 + 9$ $P= 15 + 7.5$ $P = 22.5$ ft Therefore the perimeter of the large triangle is $22.5$ ft.
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