## Basic College Mathematics (9th Edition)

Published by Pearson

# Chapter 8 - Geometry - 8.6 Circles - 8.6 Exercises: 29

#### Answer

Difference in the area: 65.94mi$^{2}$

#### Work Step by Step

We must find the area of each circle and then find the difference in area of the two. Area of a Circle: $A$ = $\pi$$r$$^{2}$ $A$$_{1} = (3.14)(5 mi)^{2} A$$_{1}$ = 78.5 mi$^{2}$ $A$$_{2} = (3.14)(2 mi)^{2} A$$_{2}$ = 12.56 mi$^{2}$ $A$$_{difference} = 78.5 mi^{2} - 12.56 mi^{2} A$$_{difference}$ = 65.94mi$^{2}$

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