Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.6 Circles - 8.6 Exercises: 27

Answer

Area of Watch: 0.8 in$^{2}$ Circumference of Watch: 3.1 in Area of Clock: 28.3 in$^{2}$ Circumference of Clock: 18.8 in

Work Step by Step

Area of a Circle: $A$ = $\pi$$r$$^{2}$ Area of a Circle: $A$ = $\pi$$d$$^{2}$/4 Circumference of a Circle: $\pi$$d$ Circumference of a Circle: 2$\pi$$r$ Therefore: $A$$_{watch}$ = (3.14)(1 in)$^{2}$ / 4 $A$$_{watch}$ = 0.8 in$^{2}$ $C$$_{watch}$ = (3.14)(1 in) $C$$_{watch}$ = 3.1 in $A$$_{clock}$ = (3.14)(3 in)$^{2}$ $A$$_{clock}$ = 28.3 in$^{2}$ $C$$_{clock}$ = 2(3.14)(3 in) $C$$_{clock}$ = 18.8 in
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.