# Chapter 8 - Geometry - 8.6 Circles - 8.6 Exercises: 27

Area of Watch: 0.8 in$^{2}$ Circumference of Watch: 3.1 in Area of Clock: 28.3 in$^{2}$ Circumference of Clock: 18.8 in

#### Work Step by Step

Area of a Circle: $A$ = $\pi$$r$$^{2}$ Area of a Circle: $A$ = $\pi$$d$$^{2}$/4 Circumference of a Circle: $\pi$$d Circumference of a Circle: 2\pi$$r$ Therefore: $A$$_{watch} = (3.14)(1 in)^{2} / 4 A$$_{watch}$ = 0.8 in$^{2}$ $C$$_{watch} = (3.14)(1 in) C$$_{watch}$ = 3.1 in $A$$_{clock} = (3.14)(3 in)^{2} A$$_{clock}$ = 28.3 in$^{2}$ $C$$_{clock} = 2(3.14)(3 in) C$$_{clock}$ = 18.8 in

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