Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 21

Answer

$A$$_{laptop}$ = 96 in $^2$ $A$$_{notebook}$ = 77 in $^2$ $A$$_{dif}$ = 19 in $^2$

Work Step by Step

To determine the difference in the areas we must determine each area and then subtract the smallest from the largest. The laptop screen is 12.3 in. x 7.8 in. Therefore: $A$$_{1}$ = 12.3 in x 7.8 in $A$$_{1}$ = 95.94 in $A$$_{1}$(To the nearest whole number) = 96 in $^2$ The notebooks screen is 10.3 in. x 7.5 in. Therefore: $A$$_{2}$ = 10.3 in x 7.5 in $A$$_{2}$ = 77.25 in $A$$_{2}$(To the nearest whole number) = 77 in $^2$ Therefore, the difference in area is $A$$_{1}$ - $A$$_{2}$. $A$$_{dif}$ = 96 in - 77 in $A$$_{dif}$ = 19 in $^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.