## Basic College Mathematics (9th Edition)

$P$ = 78 in $A$ = 234 in$^{2}$
To find the perimeter add all of the length of sides together. $P$ = 6 in + 6 in + 6 in + 9 in + 12 in + 6 in + 6 in + 15 in + 6 in + 6 in $P$ = 78 in To find the area we can break the shape into three sections. The first measuring 6 in x 6 in, the second measuring 12 in x 9 in, and the third measuring 6 in x 15 in. Find the area of each, and then add the results together to determine the total area. $A$$_{1} = 6 in * 6 in A$$_{1}$ = 36 in$^{2}$ $A$$_{2} = 12 in * 9 in A$$_{2}$ = 108 in$^{2}$ $A$$_{3} = 6 in * 15 in A$$_{3}$ = 90 in$^{2}$ $A$ = $A$$_{1} + A$$_{2}$ + $A$$_{3}$ $A$ = 36 in$^{2}$ + 108 in$^{2}$ + 90 in$^{2}$ $A$ = 234 in$^{2}$