Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises: 17

Answer

$P$ = 78 in $A$ = 234 in$^{2}$

Work Step by Step

To find the perimeter add all of the length of sides together. $P$ = 6 in + 6 in + 6 in + 9 in + 12 in + 6 in + 6 in + 15 in + 6 in + 6 in $P$ = 78 in To find the area we can break the shape into three sections. The first measuring 6 in x 6 in, the second measuring 12 in x 9 in, and the third measuring 6 in x 15 in. Find the area of each, and then add the results together to determine the total area. $A$$_{1}$ = 6 in * 6 in $A$$_{1}$ = 36 in$^{2}$ $A$$_{2}$ = 12 in * 9 in $A$$_{2}$ = 108 in$^{2}$ $A$$_{3}$ = 6 in * 15 in $A$$_{3}$ = 90 in$^{2}$ $A$ = $A$$_{1}$ + $A$$_{2}$ + $A$$_{3}$ $A$ = 36 in$^{2}$ + 108 in$^{2}$ + 90 in$^{2}$ $A$ = 234 in$^{2}$
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