Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Review Exercises - Page 257: 65

Answer

$\frac{1}{16}$

Work Step by Step

$(\frac{2}{3})^{2} \times (\frac{3}{8})^{2}$ = $\frac{4}{9} \times \frac{9}{64}$ = $\frac{1}{1} \times \frac{1}{16}$ = $\frac{1}{16}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.