Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - Review Exercises: 63

Answer

$\frac{1}{2}$

Work Step by Step

$8(\frac{1}{4})^{2}=8\times(\frac{1}{4}\times\frac{1}{4})=8\times(\frac{1\times1}{4\times4})=8\times\frac{1}{16}=\frac{8}{16}=\frac{8\div8}{16\div16}=\frac{1}{2}$
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