Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises - Page 220: 32

Answer

$ \frac{7}{15}$.

Work Step by Step

$\frac{4}{5} - \frac{1}{3} = \frac{4 \cdot 3}{5 \cdot 3} - \frac{1 \cdot 5}{3 \cdot 5} = \frac{12}{15} - \frac{5}{15} = \frac{12-5}{15} = \frac{7}{15}$.
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