Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 3 - Adding and Subtracting Fractions - 3.3 Adding and Subtracting Unlike Fractions - 3.3 Exercises: 27

Answer

$\frac{7}{15} $.

Work Step by Step

$\frac{2}{3} - \frac{1}{5} = \frac{2 \cdot 5}{3 \cdot 5} - \frac{1 \cdot 3}{5 \cdot 3} = \frac{10}{15} - \frac{3}{15} = \frac{10 - 3}{15} = \frac{7}{15} $.
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