## Basic College Mathematics (9th Edition)

$1\frac{1}{2}$
$\frac{9}{10}\div\frac{3}{5}=\frac{9}{10}\times\frac{5}{3}=\frac{9\times5}{10\times3}=\frac{45}{30}=\frac{45\div15}{30\div15}=\frac{3}{2}$ Divide 3 by 2. $3\div2=1$ with a remainder of 1 Therefore, $\frac{3}{2}=1\frac{1}{2}$.