Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 2 - Multiplying and Dividing Fractions - 2.3 Factors - 2.3 Exercises - Page 130: 30

Answer

C

Work Step by Step

In order to find the prime factorization of 36, we can try to divide 36 by the first prime, 2. $36\div2=18$ Try to divide 18 by 2. $18\div2=9$ 9 cannot be divided by 2, so we divide 9 by the next prime number, 3. $9\div3=3$ 3 itself is a prime number, so we cannot simplify any more. The prime factorization of 36 is $2\times2\times3\times3=2^{2}\times3^{2}$.
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