## Basic College Mathematics (9th Edition)

$2 \times 3^{2} \div 2 = 9$
Follow BEDMAS. In this case, we have Exponents, Division and Multiplication General equation $= a \times b \div c$ 1. Expand the exponent $3^{2} = b$ $3^{2} = 3 \times 3 = 9 = b$ 2. Divide $b$ by $c = b \div c$ $9 \div 2 = \frac{9}{2}$ 3. Multiply the last number by $(b \div c)$ $x = (a \times (b \div c))$ $x = (2 \times \frac{9}{2})$ $x = \frac{18}{2}$ $x = 9$