Answer
No, the volumes will be different.
Work Step by Step
$Volume_{1}$ = $\frac{\pi r^{2} h}{3}$
$Volume_{1}$ = $\frac{\pi \times (6 cm)^{2} \times 8 cm }{3}$
$Volume_{1}$ = 96 $\pi$ $cm^{3}$
$Volume_{2}$ = $\frac{\pi r^{2} h}{3}$
$Volume_{2}$ = $\frac{\pi \times (12 cm)^{2} \times 4 cm }{3}$
$Volume_{2}$ = 192 $\pi$ $cm^{3}$