Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises - Page 423: 37

Answer

96

Work Step by Step

We first find l: $ l = \sqrt{(\sqrt{34})^2-3^2} = \sqrt{25}=5$ Thus, we add the areas: $A = 4(1/2)(6)(5) + 6^2 = 96$
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