Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Section 9.2 - Pyramids, Area, and Volume - Exercises - Page 423: 36b

Answer

$V = \frac{\sqrt2e^3}{12}$

Work Step by Step

The volume equals 1/3 of the area of the base times the height. WE use the results from part a of both 35 and 36: V= $(1/3) \frac{\sqrt2}{\sqrt3}e(\frac{e^2\sqrt3}{4})=\frac{\sqrt2e^3}{12}$
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