Answer
615 $in.^{3}$
Work Step by Step
Area of the base = $\frac{5 \times side \times apothem }{2}$
Area of the base = $\frac{5 \times 6 in. \times 4,1 in. }{2}$
Area of the base = 61, 5 $in.^{2}$
Volume = Area of the base $\times$ h
Volume = 61, 5 $in.^{2}$ $\times$ 10 in.
Volume = 615 $in.^{3}$