Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Review Exercises - Page 447: 23

Answer

V=$\frac{32}{3}$$\pi$ in$^3$

Work Step by Step

V=$\frac{4}{3}$$\pi$(2$^3$) V=$\frac{32}{3}$$\pi$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.