Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 9 - Review Exercises - Page 447: 15c

Answer

V=72$\pi$$\sqrt 3$$\approx$391.8 cm$^3$

Work Step by Step

r=.5l r=6 h=r$\sqrt 3$ h=6$\sqrt 3$ V=$\frac{1}{3}$Bh V=$\frac{1}{3}$($\pi$6$^2$)(6$\sqrt 3$) V=72$\pi$$\sqrt 3$$\approx$391.8 cm$^3$
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