Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 392: 29

Answer

A=$\frac{1}{2}$$\pi$s$^2$-s$^2$

Work Step by Step

Diameter=s$\sqrt 2$ Radius=$\frac{1}{2}$s$\sqrt 2$ A$_{circle}$=$\frac{1}{2}$$\pi$s$^2$ A$_{square}$=s$^2$ A=A$_{circle}$-A$_{square}$ A=$\frac{1}{2}$$\pi$s$^2$-s$^2$
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