Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 392: 20

Answer

(144 - 36$\pi )m^{2}$

Work Step by Step

Area of square = Area of shaded Region + 4 * Area of $\frac{1}{4}$ circle Area of shaded region = Area of square - 4 * $\frac{1}{4}$area of circle Area of shaded region = Area of square - Area of Circle As we know area of square = $side^{2}$ = $12^{2}$ = 144 $m^{2}$ Area of Circle = $\pi r^{2}$ = $\pi 6^{2}$ = 36$\pi m^{2}$ Area of shaded region = (144 - 36$\pi )m^{2}$
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