Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.5 - More Area Relationships in the Circle - Exercises - Page 391: 11

Answer

1in

Work Step by Step

A circle is inscribed in a triangle having sides of length 3in, 4in and 5in the area of the triangle 6 $in^{2}$ Where P represents the perimeter of a triangle and r represents the length of the radius of its inscribed circle, the area of the triangle is given by A = $\frac{1}{2}$rP Perimeter of triangle = 3+4+5 = 12 in. 6 = $\frac{1}{2}$*r*12 6= 6r r = 1in Therefore the radius of the inscribed circle = 1 in.
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