Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 386: 42

Answer

$\approx$16.76 feet per second

Work Step by Step

Given The radius of the Ferris wheel’s circular path is 40 ft. If a “ride” of 12 revolutions is made in 3 minutes, at what rate in feet per second is the passenger in a cart moving during the ride Given radius of the wheel = 40 ft So one revolution = circumference of the wheel = 2 * $\pi$ * 40 = 80$\pi$ The wheel rotate 12 times for a ride, So total circumference = 12 * 80$\pi$ = 960 $\pi$ As we know speed = $\frac{distance}{time}$ = $\frac{ 960 \pi}{ 3 min}$ = $\frac{960 \pi}{180 sec}$ ( as we know 1 min = 60 sec) = 16.76 feet per sec So the passenger in a cart moving during the ride at a rate of 16.76 feet per second.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.