Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 359: 7

Answer

equal

Work Step by Step

Given $\triangle$ ABC is an obtuse triangle with obtuse angle A and $\triangle$ DEF is an acute angle triangle. Step 1 we need to compare the area We know area of $\triangle$ = $\frac{1}{2}$ bh. Therefore area of $\triangle$ ABC = $\frac{1}{2}$ * AB * H =$\frac{1}{2}$ * 8 * 6. Therefore area of $\triangle$ ABC = 24$unit^{2}$ area of $\triangle$ DEF = $\frac{1}{2}$ * DE * H =$\frac{1}{2}$ * 8 * 6. Therefore area of $\triangle$ DEF = 24$unit^{2}$ we can easily see that area of $\triangle$ ABC = area of $\triangle$ DEF = 24$unit^{2}$. Therefore area of $\triangle$ ABC = area of $\triangle$ DEF.
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