Answer
equal
Work Step by Step
Given $\triangle$ ABC is an obtuse triangle with obtuse angle A and $\triangle$ DEF is an acute angle triangle.
Step 1 we need to compare the area
We know area of $\triangle$ = $\frac{1}{2}$ bh.
Therefore area of $\triangle$ ABC = $\frac{1}{2}$ * AB * H
=$\frac{1}{2}$ * 8 * 6.
Therefore area of $\triangle$ ABC = 24$unit^{2}$
area of $\triangle$ DEF = $\frac{1}{2}$ * DE * H
=$\frac{1}{2}$ * 8 * 6.
Therefore area of $\triangle$ DEF = 24$unit^{2}$
we can easily see that area of $\triangle$ ABC = area of $\triangle$ DEF = 24$unit^{2}$.
Therefore area of $\triangle$ ABC = area of $\triangle$ DEF.