Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 7 - Review Exercises - Page 349: 24

Answer

a) BG = 12 b) GE = 2 c) DG = $8\sqrt3$

Work Step by Step

a) A theorem states that BG equals 2/3 of BF. Thus: $BG = 18 \times (2/3) = 12 $ b) GE is half of AG. Thus: $GE = .5(4) = 2$ c) Using the same method as in b), we know that DG is twice the value of CG. Thus: $ DG = 2 (4\sqrt{3}) = 8\sqrt3$
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