Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 268: 39c

Answer

CE = 10/3 EA = 8/3

Work Step by Step

We first create a proportion, and then we substitute: $\frac{BC}{BF} = \frac{AC}{FA} \\ \frac{5}{BF} = \frac{4}{6 - BF} \\BF =30/9 = 10/3$ Since FA equals $6 - BF$, it follows: $EA = \frac{18}{3} - \frac{10}{3} = 8/3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.