Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 266: 12

Answer

a=2 or 9 EC=3 or 24

Work Step by Step

$\frac{AD}{AE}$=$\frac{DB}{EC}$ $\frac{5}{a+1}$=$\frac{a+3}{3(a-1)}$ 15a-15=a^$2$+4a+3 a$^2$-11a+18=0 (a-2)(a-9)=0 a=2 or 9 EC=3a-3 EC=3 or 24
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.