Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 258: 22

Answer

AC$\approx$13.9

Work Step by Step

2BE=DB 2BE=8 BE=4 BE$^2$+AE$^2$=AB$^2$ AE$^2$=64-16 AE=$\sqrt {48}$ AC=2AE AC=2$\sqrt {48}$ AC$\approx$13.9
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