#### Answer

$\overline{DE}=12$

#### Work Step by Step

Let $b = \overline{DE}$
$13^{2} = 5^{2}+ b^{2}$
Isolate $b$
$13^{2}-5^{2}=b^{2}$
$169-25=b^{2}$
$144=b^{2}$
Square root each side
$12=b$

Published by
Brooks Cole

ISBN 10:
1439047901

ISBN 13:
978-1-43904-790-3

$\overline{DE}=12$

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