Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 5 - Review Exercises - Page 274: 27

Answer

EO=1.2 EK=9

Work Step by Step

$\frac{EO}{FG}$=$\frac{EM}{FG+GH}$ $\frac{EO}{2}$=$\frac{6}{10}$ 5EO=6 EO=1.2 $\frac{EK}{FG+GH+HJ}$=$\frac{EO}{FG}$ $\frac{EK}{15}$=$\frac{1.2}{2}$ 2EK=18 EK=9
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