Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 3 - Section 3.5 - Inequalities in a Triangle - Exercises - Page 167: 34

Answer

See the picture below:

Work Step by Step

Assuming, that $\overline{AC}=\overline{AB}=\overline{BC}$ triangle ABC is an equilateral triangle. This means $\angle ABC = 60^{\circ}$. But $\angle ABC = 90^{\circ}$ because ABCD is a square. Therefore $\overline{AC} \ne \overline {AB}$.
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