# Chapter 3 - Section 3.2 - Corresponding Parts of Congruent Triangles - Exercises: 34

Alinna traveled 4 miles farther by using alternative route from A to B

#### Work Step by Step

According to question AC=5 miles and CB=12 miles $\triangle$ABC is right angled triangle $AB^{2}$=$AC^{2}$+$CB^{2}$ $AB^{2}$=$5^{2}$+$12^{2}$ $AB^{2}$=25+144 $AB^{2}$=169 AB=$\sqrt 169$=13 Now we have to find how much farther Alinna traveled so it will be, AC+CB-AB 5+12-13=4 miles

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